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Propene is allowed to react with HBr in ...

Propene is allowed to react with `HBr` in the presence of benzoyl peroxide and the product is subsequently heated with aqueous `KOH`. The final product obtained is

A

propane -`1-ol`

B

propane-`2-ol`

C

propane-`1,2`-diol

D

propane-`1,3`-diol

Text Solution

Verified by Experts

The correct Answer is:
A
`CH_(3)CH = CH_(2) underset((C_(6)H_(5)CO)_(2)O_(2)) overset(HBr)rarr CH_(3)CH_(2)CH_(2)Br overset(aq.KOH)rarrCH_(3)underset("Propan-1-ol")(CH_(2)OH)`
First step involves anti-Markovnikov addition while the second step involves hydrolysis of halide.
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Knowledge Check

  • When HB adds on hex-1-ene in the presence of benzoyl peroxide, the product is

    A
    2-bromohexane
    B
    2,3-dibromohexane
    C
    1.2-dibromohexane
    D
    1-bromohexane

  • When HBr adds on hex-1-ene in the presence of benzoyl peroxide, the product is

    A
    2-bromohexane
    B
    2, 3-dibromohexane
    C
    1,2-dibromohexane
    D
    1-bromohexane

  • When HBr is added to hex-1-ene in the presence of benzoyl peroxide, the product is

    A
    1-bromohexane
    B
    2-bromohexane
    C
    2,3-dibromohexane
    D
    3-bromohexane

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    When 3-phenyl propene is treated with HBr in the presence of proxide, the major product formed is

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