Which of the following is a constitutionally symmetrical ether?

Options

A.
B.
C.
D.

Answer

A

Explanation

When the two hydrocarbon group in an ether are idential, the ether is said to be symetrical or simple. When the two hydrocarbon groups are different, the ether is said to be unsymmetrical or mixed.
Compound `(1)` is a symmetrical ether as the two alkyl groups bonded to oxygen are the same.
`H_(3)C-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C )-O-overset(CH_(3))overset(|)underset(CH_(3))underset(|)(C )-CH_(3)`
Compound `(2)` is an unsymmetrical ether as the alkyl groups bonded to oxygen are different. compound `(3)` is an ester while compound `(4)` is an anhydride.