In the reaction given below, `X` is
Neopentyl alcohol `overset(H_(2)SO_(4))(rarr)X`

Options

A. `2-`methylpentane
B. `2-`methylpent-2-ene
C. `2-`methylbut`-2-`ene
D. neopentane

Answer

C

Explanation

`overset(~CH_(3^( : ))^(-))underset(-H_(2)O)(rarr)CH_(3)-overset(CH_(3))overset(|)underset(+)(C )-CH_(2)CH_(3)overset(-H^(+))(rarr)underset(2"Methylbut" 2-"ene")(CH_(3)-overset(CH_(3))overset(|)(C )=CHCH_(3))`
Formation of a neopentyl cation `(1^(@) "Cation")` is unlikely. instead, a Methyl group migrating from the adjacent carbon acts as an intramolecular nucleophile, helping to displace `H_(2)O`. The result is a `3^(@)C^(+)`, from which the alkene is formed.