Volume required for neutralization: What volume of 0.100 N HCl solution is required to netralize completely 50.0 mL of a `0.150 N` solution of `Ba(OH)_(2)`?
Strategy: We know three of the four variables in the relationship.
`mL_(acid)xxN_(acid)=mL_(base)xxN_(base)`
and so we solve for `mL_(acid)`

Explanation

`mL_(acid)=(mL_(base)xxN_(base))/N_(acid)=(50.0 mLxx0.150 N)/(0.100N)`
`=75 mL of HCl` solution