The reaction `A(g)rarrB(g)` is found to be zero order with respect to A(g) Which of the following is correct ?

Options

A. Graph between [A] and time t is a straight line with `-ve` slope and zero intercept
B. Graph between [A] and time t is a straight line with `+ve` slope and nonzero intercept
C. Graph between [A] and time t is a straight T line with `-ve` slope nonzero intercept
D. Graph between [A] and time t is a straight line with zero slope and nonzero intercept

Answer

C

Explanation

The integrated rate law for a zeroth order reaction of the type `A(g)rarrB(g)` is
`[A]==-Kt+[A]_(0)`
This is an equation of the from `y=mx+b` , so a graph of `[A]` versus time is a straigh line with a negative slope `=-K` and intercept equal to `[A]_(0)`