The integrated rate expression for a first order reaction can be written as

Options

A. (a-x)=a exp `(-k_(1)t)`
B. x=a exp `(-k_(1)t)`
C. (a-x)=t exp `(-k_(1)t)`
D. (a-x)=a exp `(-k_(1)//t)`

Answer

A

Explanation

Let the reaction be
`{:(a" "0" ""initial concentration"),(A" "to" "B" "),((a-x)" "x" ""concentration at time"t):}`
`In(a-x)/(a)=-K_(1)t)`
or `(a-x)/(a)=e^(-K_(1)t)`
In the above expression `(a-x)` will be zero only at infinite time.