Two reaction proceed at `35^(@)C` at the same rate. The temperature coefficient of the first reaction is 4 and thatr of the second is 2. The ratio of the rates of these reaction at `75^(@)C` is

Options

A. 2
B. 4
C. 16
D. 8

Answer

C

Explanation

At `35^(@)C` the rates of the two reactions are same (say `R`) Since the temperature coefficient tells us how many times the reaction rate increases by a rise in temperature of `10^(@)` we have the following results.

Thus, at `75^(@)C` ,
`("rate of second reaction")/("rate of first reaction")=(4^(4)R)/(2^*4)R=16`