The rate constant of the reaction `A rarr B` is `0.6 xx 10^(-3)` mole per second. If the concentration of `A` is `5 M`, then concentration of `B` after `20` minutes is:

Options

A. `0.36M`
B. `0.72M`
C. `1.08M`
D. `3.60M`

Answer

B

Explanation

Units of rate constant indicate that it is a zero order reaction. Its integrated rate law is
`x=kt`
where `x` is the concentration of product at time `t` . Substituting the values, we get
`x=(0.6xx10^(-3)mole//L.s)(2.0min)((60s)/(min))`
`=0.72mol//L` or `0.72M`