The resonating structure of `NO` are represented by

Options

A. `.overset(..)N=overset(..)underset(..)O:harr.overset(+)overset(..)N equiv overset(-)overset(..)O`
B. `:overset(.)N=overset(..)underset(..)Oharr:overset(-)overset(..)N=overset(+)overset(.)O:`
C. `N=overset(..)O:harr:N=overset(..)O`
D. `:N=O:harr:Nequivoverset(..)O`

Answer

B

Explanation

The structure of the molecules is a reasonance hybrid of the two forms:
`:overset(.)N=overset(..)O:harr:overset(-)overset(..)N=overset(+)overset(.)O:`
The bond length `N-O` is `115`pm, which is intermediate between a double and a triple bond.
Nitric oxide readily loses its unpaired electron from the antibonding orbital to form the nitrosyl ion `(NO^(+))`, which is diamagnetic and has a shorter`N-O` bond length `(106 p m)` then that of the parent molecules `(115 p m)`. This triple-bonded (bond order is `3`) ion is isoelectronic with `CO,` and `N_(2)`. It forms many analofous metal complexes.