Which of the following is not correct in the context of the `NO_(3)^(-)` ions?

Options

A. The bond order of each `N-O` bond is `4//3`
B. The bond order of each `N-O` bond is `3//2`
C. The geometry and shape of the `NO_(3)^(-)` ion is planar triangular
D. All the three oxygen atoms are equivalent

Answer

2

Explanation

The geometry as well as shape of the nitrate ion is a planar triangle. All three `O` atoms are equivalent. In addition to the `sigma` bond. Four- centre `pi` molecular orbitals cover the`N`and the three`O`atoms. Each of the `N-O` bonds has a bond order of,`1(1)/(3)(1.33)`, 1 from the `sigma` bond and `1//3` from the `pi` bond.