Oxygen difluoride`(OF)`, a pale yellow gas ,is prepared by passing `F_(2)` into

Options

A. concentrated `NH_(3)` solution
B. concentrated `NaOH` solution
C. dilute `NaOH_(4)` solutions
D. dilute `NaOH` solution

Explanation

To solve the question regarding the preparation of oxygen difluoride (OF2) by passing fluorine gas (F2) into a solution, we can follow these steps:

### Step-by-Step Solution:

1. **Identify the Compound**: The compound we are preparing is oxygen difluoride, represented as OF2. It is described as a pale yellow gas.

2. **Understand the Reaction**: The question states that OF2 is prepared by passing F2 into a solution. We need to determine which solution is suitable for this reaction.

3. **Consider Possible Solutions**: The options provided likely include various aqueous solutions. One common solution that reacts with fluorine is dilute sodium hydroxide (NaOH).

4. **Write the Reaction**: When F2 is passed through a dilute NaOH solution, the following reaction occurs:
\[ 2 \text{NaOH} + \text{F}_2 \rightarrow \text{OF}_2 + \text{NaF} + \text{H}_2\text{O} \]
This indicates that oxygen difluoride (OF2) is produced along with sodium fluoride (NaF) and water (H2O).

5. **Conclusion**: Based on the reaction, we conclude that the correct solution to prepare OF2 is dilute sodium hydroxide (2% NaOH). Therefore, the answer to the question is that OF2 is prepared by passing F2 into dilute NaOH.

### Final Answer:
Oxygen difluoride (OF2) is prepared by passing F2 into dilute sodium hydroxide (2% NaOH) solution.

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