Xenon fluorides are all extermely strong

Options

A. reducing agent
B. oxidizing agent
C. flourinating agents
D. both (2) and (3)

Answer

4

Explanation

They are all extremely strong oxidizing and fluorinating agents. They react quantitatively with hydrogen as follows:
`XeF_(2)+H_(2)rarr2HF+Xe`
`XeF_(4)+2H_(2)rarr4HF+Xe`
`XeF_(6)+3H rarr 6HF+Xe`
They oxidizes chloride to chlorine iodide to cerium `(+3)` to cerium `(+4)`:
`XeF_(2)+2HCl rarr Cl_(2)+2HF+Xe`
`XeF_(4)+4Kl rarr 2I_(2)+4KF+Xe`
`SO_(4)^(2-)+XeF_(2)+Ce_(2)(SO_(4))_(4)rarr2Ce(SO_(4))_(2)+F_(2)+Xe`
They fluorinate compounds:
`XeF_(4)+C_(6)H_(6)rarrC_(6)H_(5)F+Xe+HF`
`XeF_(4)+Pt rarr PtF_(4)+Xe`
`XeF_(4)+2SF_(4)rarr2SF_(6)+Xe`