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PH(4)I+NaOH rarr? The product is...

`PH_(4)I+NaOH rarr`?
The product is

A

`P_(4)O_(10)`

B

`P_(4)O_(6)`

C

`NH_(3)`

D

`PH_(3)`

Text Solution

Verified by Experts

The correct Answer is:
4
The impure phosphine gas may be purified by treating it with hydrogen iodide followed by heating the phosphonium iodide thus formed with caustic soda solution
`PH_(3)+HI rarr PH_(4)I`
`PH_(4)I+NaOH rarr PH_(3)+NaI+H_(2)O`
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