A beam of charged particle, having kinetic energy `10^3 eV`, contains masses `8xx10^(-27) kg and 1.6xx10^(-26) kg` emerge from the end of an accelerator tube. There is a plate at distance `10^2 m` from the end of the tube and placed perpendicular to the beam. Calculate the magnitude of the smallest magnetic field which can prevent the beam from striking the plate.

Explanation

`R = (sqrt(2m K))/(Bq) = (sqrt(2 mK))/(Be)`
`(sqrt(2mK))/(Be) le R(= 0.01)`
`(sqrt(2mK))/(e(0.01)) le B or B ge (sqrt(2mK))/(e(0.01))`
For minimum `B`, `m` should be greater, hence `m = 1.6 xx 10^(-26) kg`
`B_(min) = (sqrt(2 xx 1.6 xx 10^(-26) xx 10^(3) xx 1.6 xx 10^(-19)))/(1.6 xx 10^(-19)(0.01))`
`= sqrt(2) T`