A beam of equally charged particles after being accelerated through a voltage `V` enters into a magnetic field `'B'` as shown. It is found that all the particles hit the plate between `X` and `Y`. Find the ration between the masses of the heaviest and lightest particles of the beam.

Explanation

`R = (mv)/(Bq) = sqrt((2m K)/(Bq)) = sqrt(2m q V)/(Bq)`
`R prop m`
The radius of heaviest particle `R_(1) = a + b`
The radius of lightest particle `R_(2) = a`
`(R_(1))/(R_(2)) = sqrt((m_(1))/(m_(2)))`
`(a + b)/(a) = sqrt((m_(1))/(m_(2)))`
`(m_(1))/(m_(2)) = ((a + b)/(a))^(2)`