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A coil having N turns is wound tightly i...

A coil having N turns is wound tightly in the form of a spiral with inner and outer and radii a and b respectively . When a current I passes through the coil, the magnetic field at the center is

A

`(qbB)/(m)`

B

`(q(b - a)B)/(m)`

C

`(qaB)/(m)`

D

`(q(b + a)B)/(m)`

Text Solution

Verified by Experts

The correct Answer is:
B


`R = (mv)/(Bq)`
If particle just enters `x gt b`,
`R ge (b - a)`
`(mv)/(Bq) ge (b - a)`
`v ge (Bq(b - a))/(m)`
`v_(min) = (q(b - a)B)/(m)`
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