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A small circular flexible loop of wire o...

A small circular flexible loop of wire of radius `r` carries a current `I`. It is placed in a uniform magnetic field `B`. The tension in the loop will be doubled if (Choose the incorrect option)

A

`I` is doubled

B

`B` is doubled

C

`r` is doubled

D

both `B` and `I` are doubled

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The correct Answer is:
To solve the problem, we need to analyze how the tension in a circular loop carrying current in a magnetic field is affected by changes in current (I), magnetic field strength (B), and radius (r). ### Step-by-Step Solution: 1. **Understanding the Force on the Loop**: - The magnetic force \( F_m \) acting on a small segment of the loop can be expressed as: \[ F_m = I \cdot L \cdot B \cdot \sin(\theta) \] - For a small angle \( \theta \), we can approximate \( \sin(\theta) \approx \theta \). 2. **Length of the Segment**: - For a small segment of the loop, the length \( L \) can be represented as: \[ L = r \cdot d\theta \] - Here, \( r \) is the radius of the loop and \( d\theta \) is the small angle in radians. 3. **Magnetic Force Calculation**: - Substituting \( L \) into the magnetic force equation gives: \[ F_m = I \cdot (r \cdot d\theta) \cdot B \cdot \sin(\theta) \approx I \cdot (r \cdot d\theta) \cdot B \] 4. **Tension in the Loop**: - The vertical component of the tension \( T_y \) must balance this magnetic force. Therefore, we can express the total tension in the loop as: \[ T_y = I \cdot r \cdot B \] 5. **Effect of Doubling Variables**: - If we double the current \( I \), the new tension becomes: \[ T_y' = 2I \cdot r \cdot B = 2T_y \] - If we double the magnetic field \( B \), the new tension becomes: \[ T_y' = I \cdot r \cdot (2B) = 2T_y \] - If we double the radius \( r \), the new tension becomes: \[ T_y' = I \cdot (2r) \cdot B = 2T_y \] 6. **Combining Changes**: - If we double both \( I \) and \( B \) simultaneously: \[ T_y' = (2I) \cdot r \cdot (2B) = 4I \cdot r \cdot B = 4T_y \] - This shows that the tension quadruples when both current and magnetic field are doubled. 7. **Conclusion**: - The tension in the loop will be doubled if we double \( I \), \( B \), or \( r \) individually. However, if we double both \( I \) and \( B \) together, the tension will be quadrupled, not doubled. Therefore, the incorrect option is the one that states the tension will be doubled when both \( I \) and \( B \) are doubled. ### Incorrect Option: - The incorrect option is the one that states that the tension will be doubled if both the current \( I \) and the magnetic field \( B \) are doubled.

To solve the problem, we need to analyze how the tension in a circular loop carrying current in a magnetic field is affected by changes in current (I), magnetic field strength (B), and radius (r). ### Step-by-Step Solution: 1. **Understanding the Force on the Loop**: - The magnetic force \( F_m \) acting on a small segment of the loop can be expressed as: \[ F_m = I \cdot L \cdot B \cdot \sin(\theta) ...
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