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A rectangular loop of sides 20 cm and 10...

A rectangular loop of sides `20 cm` and `10 cm` carries a current of `5.0 A`. A uniform magnetic field of magnitude `2 T` exists parallel to the longer side of the loop. The torque acting on the loop is

A

`0.2 Nm`

B

`0.3 Nm`

C

`2 Nm`

D

`3 Nm`

Text Solution

Verified by Experts

The correct Answer is:
A

`tau = MB sin theta = iAB sin 90^(@) = i(l xx b)B`
`= 5(20 xx 10 xx 10^(-4)) xx 2`
`= 0.2 Nm`
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