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A current carrying loop is free to turn ...

A current carrying loop is free to turn in a uniform magnetic field.The loop will then come into equilibrium when its plane is inclined at

A

`0^(@)` to the direction of the field

B

`45^(@)` to the directed of the field

C

`90^(@)` to the directed of the field

D

`135^(@)` to the directed of the field

Text Solution

Verified by Experts

The correct Answer is:
C

`U =-vec(M) . vec(B) = -MB cos theta`
Equilibrium will be stable if `U` is minimum. It will happen when
`theta =0^(@), U_(min) = -MB`
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