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The binding energies per nucleon for a d...

The binding energies per nucleon for a deuteron and an `alpha-`particle are `x_1` and `x_2` respectively. What will be the energy `Q` released in the following reaction ?
`._1H^2 + ._1H^2 rarr ._2He^4 + Q`.

A

`4(x_(1)+x_(2))`

B

`4(x_(2)-x_(1))`

C

`2(x_(1)+x_(2))`

D

`2(x_(2)-x_(1))`

Text Solution

Verified by Experts

The correct Answer is:
B
`._(1)H^(2) +._(1)H^(2) rarr._(2)He^(4) +Q`
`Q -` value `= 4x_(2) - 4x_(1) = 4(x_(2)-x_(1))`
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