In the nuclear reaction : X (n, alpha)3 ...

In the nuclear reaction : `X (n, alpha)_3 Li^7` the term `X` will be `3`

`._(5)B_(10)`

`._(5)B^(9)`

`._(5)B^(11)`

`._(2)He^(4)`

Text Solution

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The correct Answer is:

`._(Z)X^(A) +._(0)n^(1) rarr ._(2)He^(4) +._(3)Li^(7)`
`Z +0 = 2+3 rArr Z = 5`
`A+1 = 4+7 rArr A = 10`
`X` is `._(5)B^(10)`

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