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To produce an electron-position pair, th...

To produce an electron-position pair, the minimum energy of `gamma`-ray photon must be

A

`1.02keV`

B

`1.02MeV`

C

`1.02BeV`

D

`1.02eV`

Text Solution

Verified by Experts

The correct Answer is:
B
Rest energy of electron `= (9.1xx10^(-31)xx(3xx10^(8))^(2))/(1.6xx10^(-13))MeV`
`= 0.510 MeV`
`gamma rarr e^(+) +e^(-)`
Energy of photon `= 2xx0.51 = 1.02MeV`
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