Let `m_(p)` be the mass of a poton , `M_(1)` the mass of a `_(10)^(20) Ne` nucleus and `M_(2)` the mass of a `_(20)^(40) Ca` nucleus . Then

Options

A. `(i),(iv)`
B. `(ii),(iv)`
C. `(ii),(iii)`
D. `(iii),(iv)`

Answer

D

Explanation

`M_(1) lt 10(m_(p) +m_(n))M_(2) lt 20(m_(p)+m_(n))`
Heavier the nucleus, more is mass defect
`[20(m_(p)+m_(n))-M_(2)] gt [10(m_(p)+m_(n))-M_(1)]`
`M_(2) lt[M_(1) +10(m_(p)+m_(n))]`
`M_(2) lt 2M_(1)`