In a radioactive series, `._(92)U^(238)` charges to `._(82)Pb^(206)` through `n_(1)`(`alpha`-decay processes) and `n_(2)`(`beta-`deacy processes)

Options

A. `n_(1) = 8,n_(2) = 8`
B. `n_(1) =6, n_(2) = 2`
C. `n_(1) = 8,n_(2) = 6`
D. `n_(1) = 6,n_(2) =8`

Answer

C

Explanation

`._(92)U^(238)rarr._(82)Pb^(206)`
`(238-206)/(4) = 8 alpha-`particles
Decrease in `Z` due to `alpha`-particle `= 16` but decrease in only `92-82 = 10` i.e `6beta-`particles
`n_(1) = 8, n_(2) = 6`