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The percentage of quantity of a radioact...

The percentage of quantity of a radioactive material that remains after 5 half-lives will be .

A

`1%`

B

`3%`

C

`5%`

D

`20%`

Text Solution

Verified by Experts

The correct Answer is:
B
`N = N_(0) ((1)/(2))^(n) = N_(0)((1)/(2))^(5) = (N_(0))/(32)`
`(N)/(N_(0)) xx 100 = (100)/(32) ~~ 3%`
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