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If the binding energy per nucleon in L i...

If the binding energy per nucleon in `L i^7` and `He^4` nuclei are respectively `5.60 MeV` and `7.06 MeV`. Then energy of reaction `L i^7 + p rarr 2_2 He^4` is.

A

`-2.4MeV`

B

`8.4MeV`

C

`17.3MeV`

D

`19.6MeV`

Text Solution

Verified by Experts

The correct Answer is:
C

`._(3)^(7)Li +._(1)^(1)H rarr ._(2)^(4)He +._(2)^(4)He +Q`
`Q = 2(BE` of `He) - (BE` of `Li)`
`=2xx(4xx7.06) - (7xx5.60)`
`= 17.3 MeV`
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