The kinetic energy `(KE)` versus time graph for a graph for a particle moving along a straight line is shown in the figure. The force `vs` time graph for the particle may be
.

Options

A.
B.
C.
D.

Answer

D

Explanation

`E_(k) = (1)/(2) mv^(2) = kt , rArr` power `'P' = ((dE_(k))/(dt)) = k`
In this case, `P=Fv`
Hence, `F = (P)/(v) = (K)/(sqrt((2Kt)/(m))) = (K')/(sqrt(t))`
where `K^(1)` is another constant.