A light spring of force constant 'K' is held between two blocks of masses 'm' and '2m'. The two blocks and the spring system rests on a smooth horizontal floor. Now th blocks are moved towards each other compressing the springs by 'x' and suddenly released. The relative velocity between the blocks when the spring attains its natural length will be

Options

A. `(sqrt((3K)/(2m)))x`
B. `(sqrt((2K)/(3m)))x`
C. `(sqrt((K)/(3m)))x`
D. `(sqrt((K)/(2m)))x`

Answer

A

Explanation

Using reduced mass concept, `mu = (m_(1)m_(2))/(m_(1) + m_(2))`
`(1)/(2) mu v^(2) = (1)/(2) kx^(2)`.