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A block of wood of mass 3M is suspended ...

A block of wood of mass `3M` is suspended by a string of length `(10)/(3) m`. A bullet of mass `M` hits it with a certain velocity and gets embedded in it. The block and the bullet swing to one side till the string makes `120^@` with the initial position. the velocity of the bullet is `(g=10 ms^(-2))`.

A

`(40)/(sqrt(3)) ms^(-1)`

B

`20 ms^(-1)`

C

`30 ms^(-1)`

D

`40 ms^(-1)`.

Text Solution

Verified by Experts

The correct Answer is:
D

`m u = (M + m) sqrt(2gl(1 - cos theta))`.
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