A body A moves towards a wall with velocity `V`. The wall also moves towards the body `A` with velocity `V_(0)`. After collision the body moves in opposite direction with velocity `V^(|)` which is `(1+(2V_(0))/(V))` times the velocity `V`. The coefficient of restitution is

Options

A. `(1)/(4)`
B. `(1)/(3)`
C. `1`
D. `(1)/(2)`

Answer

C

Explanation

`e=(v_(2)-v_(1))/(u_(1)-u_(2))=(-v_(0)+v^(1))/(v+v_(0))` , given `v^(1) =(1+(2v_(0))/(v))v`.