A block of mass `m` is allowed to slide down a fixed smooth inclined plane of angle `q` and length `l`. The magnitude of power developed by the gravitational force when the block reaches the bottom is.

Options

A. `sqrt(2m^(2) l(g sin theta)^(3))`
B. `(2//3)m^(3) l g^(2) sin theta`
C. `sqrt((2//3)m^(2)l^(2) g cos theta)`
D. `(1//3)m^(3) l g^(2) sin theta`

Answer

A

Explanation

`p = vec F.vec v , mg sin theta sqrt(2gl sin theta)`
=`sqrt(2m^(2)g^(3)l sin^(3) theta)`.