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The displacement x (in m), of a patticle...

The displacement `x` (in `m`), of a patticle of mass `m` (in `kg`) is related to the time `t` (in second) by `t = sqrt(x) +3`. Find the work done in first six second. (in `mJ`).

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Verified by Experts

The correct Answer is:
`0`
`x=(t -3)^(2)=t^(2)-6t +9`
`v = (dx)/(dt) =2t - 6`
at `t =0,v =-6`'at `t =6,v = +6`
initial `KE = (1)/(2) m(-6)^(2) = 18 m`
final `KE = (1)/(2) m(6)^(2) = 18 m`.
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