A police is chasing a culprit going n a motorbike. The motorbike crosses a turning at a speed of 72 km/h.
The jeep follows it at a speed of 90 km/h, crossing the turning tenseconds latert than the bike. Assuming that they tavel at constant speeds, how far from the turning will the jeep catch up with the bike?

Answer

1

Explanation

`V_(P)=90kmh^(-1)=25ms^(-1)`
`V_(C)=72kmh^(-1)=20ms^(-1)`
in 10 s culprit reaches point B from A. Distance covered by cuprit, `S=vt=20xx10=200`m
at time `t=10s` the police jeep is 200 behind the culprit. Relative velocity between jeep culprit is `25-20=5ms^(-1)`
Time `=(S)/(V)=(200)/(5)=40s` (relative velocity is distance S where)
In 40 s the police jeep will move from A to a distance S. Where
`S=ct=25xx40=1000m=1.0km` away
The jeep will catch up with the bike 1 km far from the turning.