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An elevator car whose floor to ceiling d...

An elevator car whose floor to ceiling distance is equal to `2.7 m` starts ascending with constant acceleration `1.2 m//s^(2)`, 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question `(g=9.8 m//s^(2)`
The bolt's free falls time

A

0.3 s

B

0.5 s

C

0.7 s

D

0.9 s

Text Solution

Verified by Experts

The correct Answer is:
C
`y_(rel)=u_(rel)t+(1)/(2)a_(rel)t^(2)-2.7=0-(1)/(2)(9.8+1.2)t^(2)t=0.7sec`
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Knowledge Check

  • An elevator car whose floor to ceiling distance is equal to 2.7 m starts ascending with constant acceleration 1.2 m//s^(2) , 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question (g=9.8 m//s^(2) The velocity of bolt at instant it loses contact is

    A
    `1.2 m//s`
    B
    `2.4 m//s`
    C
    `4 m//s`
    D
    `10 m//s`

  • An elevator car whose floor to ceiling distance is equal to 2.7 m starts ascendiung with constant acceleration 1.2(m)/(s^(2)) , 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question g = 9.8 m//s^(2) Distance moved by elevator car w.r.t. ground frame during the free fall time of the bolt.

    A
    1.44 m
    B
    1.63m
    C
    1.68m
    D
    1.97m

  • An elevator car whose floor to ceiling distance is equal to 2.7 m starts ascendiung with constant acceleration 1.2(m)/(s^(2)) , 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question g=9.8 m//s^(2) Distance covered by the bolt during the free fall time w.r.t. ground frame.

    A
    0.7 m
    B
    0.9 m
    C
    1.1 m
    D
    1.3 m