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On a two lane road , car (A) is travelli...

On a two lane road , car (A) is travelling with a speed of `36 km h^(-1)`. Tho car ` B and C` approach car (A) in opposite directions with a speed of ` 54 km h^(-1)` each . At a certain instant , when the distance (AB) is equal to (AC), both being ` 1 km, (B) decides to overtake ` A before C does , What minimum accelration of car (B) is required to avoid and accident.

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The situation can be roughly shown in the figure. Let C take time t to overtake A.
`d_(rel)=1000, v_(rel)=(10+15)=25ms^(-1)`
Here `t=(d_(rel))/(v_(rel))=(1000)/(25)=40s`
Let acceleration of B be a for overtaking.
`d_(rel)=1000 m, v_(rel)=15-10=5ms^(-1)`
`d_(rel)=a and t=40s`
Using `d_(rel)=u_(rel)t+(1)/(2)a_(rel)t^(2)`
`100=5xx40+(1)/(2)a(40)^(2)impliesa=1ms^(-2)`
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