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A body moves from one corner of an equil...

A body moves from one corner of an equilateral Delta of side 10 cm to the same corner along the sides. Then the distance and displacement are respectively.

A

30 cm & 10 cm

B

30 cm & 0 cm

C

0 cm & 30 cm

D

30 cm & 30 cm

Text Solution

Verified by Experts

The correct Answer is:
B
Displacement`=`shortest distance between initial point and final point.
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Knowledge Check

  • If the side of an equilateral triangle is 10 cm, then find the area of the triangle.

    A
    `10 sqrt3 cm^(2)`
    B
    `25 sqrt3 cm^(2)`
    C
    `50sqrt3 cm^(2)`
    D
    `75 sqrt3 cm^(2)`

  • Each side of an equilateral triangle is 10 cm long. The height of the triangle is

    A
    `10 sqrt(3)` cm
    B
    `5 sqrt(3)` cm
    C
    `10 sqrt(2)` cm
    D
    5 cm

  • In an equilateral triangle ABC of side 10cm, the side BC is trisected at D. Then the length (in cm) of AD is

    A
    `3 sqrt(7)`
    B
    `7 sqrt(3)`
    C
    `(10 sqrt(7))/(3)`
    D
    `(7 sqrt(10))/(3)`
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