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An elevator car whose floor to ceiling d...

An elevator car whose floor to ceiling distance is equal to `2.7 m` starts ascending with constant acceleration `1.2 m//s^(2)`, 2 sec after the start a bolt begins falling from the ceiling of the car. Answer the following question `(g=9.8 m//s^(2)`
The velocity of bolt at instant it loses contact is

A

`1.2 m//s`

B

`2.4 m//s`

C

`4 m//s`

D

`10 m//s`

Text Solution

Verified by Experts

The correct Answer is:
B
`v=u+at=0+(1.2)(2)=2.4 m//s`
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