Home
Class 11
PHYSICS
A particle moves along x-axis satisfying...

A particle moves along x-axis satisfying the equation `x=[t(-1)(t-2)]` (t is in seconds and `x` is in meters). Find the magnitude of initial velocity of the particle in `m//s`.

Text Solution

Verified by Experts

The correct Answer is:
2

`x=t(t^(2)-3t+2)`
`=t^(3)-3t^(2)+2t`
`impliesv=3t^(2)-6t+2impliesv_(0)=2`
Promotional Banner

Topper's Solved these Questions

  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Single Answer Question|8 Videos
  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Comprehension Question|5 Videos
  • MOTION IN A STRAIGHT LINE

    NARAYNA|Exercise Multiple Answer Question|22 Videos
  • MOTION IN A PLANE

    NARAYNA|Exercise Level-II(H.W)|31 Videos
  • NEWTONS LAWS OF MOTION

    NARAYNA|Exercise PASSAGE TYPE QUESTION|6 Videos

Similar Questions

Explore conceptually related problems

A particle Moves along x axis satisfying the equation x=[t(t+1)t-2 where t is in seconds and x is in Meters Then the Magnitude of initial velocity of the particle in M/s is

A particle moves along the x-axis obeying the equation x=t(t-1)(t-2) , where x is in meter and t is in second a. Find the initial velocity of the particle. b. Find the initial acceleration of the particle. c. Find the time when the displacement of the particle is zero. d. Find the displacement when the velocity of the particle is zero. e. Find the acceleration of the particle when its velocity is zero.

A particle moves along x-axis according to the law x=(t^(3)-3t^(2)-9t+5)m . Then :-

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the magnitude of displacement (in meters) by the particle from time t = 0 to t = t will be :

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = 1 s will be :

A particle moves along x-axis and its acceleration at any time t is a = 2 sin ( pit ), where t is in seconds and a is in m/ s^2 . The initial velocity of particle (at time t = 0) is u = 0. Q. Then the distance travelled (in meters) by the particle from time t = 0 to t = t will be :

The position of a particle along the x-axis is given by the equation, x=t^(3)-6t^(2)+9t , where t is measured in seconds and x in meters. (a) Find the velocity at time t (b) What is the velocity at t = 2 s, at = t = 4 s? (c) What is the time instant, when particle is at rest?

A particle moves along the X-axis as x=u(t-2s)=at(t-2)^2 .

A particle moves along x-axis as x=4(t-2)+a(t-2)^2 Which of the following is true?

A particle moves along x-axis as x= t (t-2)+(t-2)^(2) . Which of the following is true?