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A boy standing at the top of a tower of ...

A boy standing at the top of a tower of `20 m`. Height drops a stone. Assuming `g = 10 ms^-2` towards north. The average acceleration of the body is.

A

`20ms^(-1)`

B

`40ms^(-1)`

C

`5ms^(-1)`

D

`10ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
`v=sqrt(2gh)`
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NARAYNA-MOTION IN A STRAIGHT LINE-Level 1 H.W
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