The average velocity of a body moving with uniform acceleration after travelling a distance of `3.06 m` is `0.34 m s^(-1)`. If the change in velocity of the body is `0.18 ms^(-1)` during this time, its uniform acceleration is .

Options

A. 0.01
B. 0.2
C. 0.03
D. 0.04

Answer

B

Explanation

`t=("distance")/(V_(ave)),a=("change in velocity")/("total time")=(v-u)/(t)`