Two stones are thrown vertically upwards...

Two stones are thrown vertically upwards with the same velocity of `49 m//s`. If they are thrown one after the other with a time lapse of 3 second, height at which they collide is

58.8 m

111.5 m

117.6 m

122.5 m

Text Solution

Verified by Experts

The correct Answer is:

`h=(u^(2))/(2g)-(g t^(2))/(8)`

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