A stone projected vertically up from the ground reaches a height `y` in its path at `t_(1)` seconds and after further `t_(2)` seconds reaches the ground. The height y is equal to

Options

A. `(1)/(2)g(t_(1)+t_(2))`
B. `(1)/(2)g(t_(1)+t_(2))^(2)`
C. `(1)/(2)g t_(1)t_(2)`
D. `g t_(1)t_(2)`

Answer

C

Explanation

`h=y=(1)/(2)g t_(1)t_(2)`