When two objects move uniformly towards each other, they get `4` metres closer each second and when they move uniformly in the same direction with original speed, they get `4` metres closer each `5s`. Find their individual speeds.

Explanation

Let the speeds be `v_(1)` and `v_(2)` and let `v_(1)gt v_(2)`.
In First case:
Relative velocity, `v_(1)+v_(2)=4/1=4 m//s`…..(1)
In Second case:
Relative velocity, `v_(1)-v_(2)=4/5=0.8 m//s`…..(2)
solving eqns. (1) and (2), we get
`v_(1)=2.4ms^(-1),v_(2)=1.6ms^(-1)`