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To a man walking at the rate of 3 km//h ...

To a man walking at the rate of `3 km//h` the rain appear to fall vetically douwnwards. When he increases his speed `6 km//h` it appears to meet him at an angle of `45^@` with vertically. Find the speed of rain.

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From the diagram `Tan45^(@)=3/y` …(1)
and `Tan theta =3/y`….(2)
From (1) and (2) `theta =45^(@) rArr :. sin 45^(@)=3/V_(R),1/sqrt2=3/V_(R)`
`V_(R)=3sqrt(2)` kmph
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