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A particle is projected from the ground with an initial speed `v` at an angle `theta` with horizontal. The average velocity of the particle between its point of projection and highest point of trajectory is `[EAM 2013]`

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`vecv_(avg)=(vecv+vecu)/2=(u cos theta hati+(u cos theta hati + u sintheta hat j))/(2)`
`vecv_(av)=v/2sqrt(1+3cos^(2)theta)`
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