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A particle is projected from a tower as shown in figure, then find the distance from the foot of the tower where it will strike the ground. `(g=10m//s^(2))`

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`u_(y)=u sin theta =500/3sin37^(@)`
`s=ut+1/2at^(2)`
`1500=(500/3sin37)t+1/2(10t)^(2)`
`1500=500/3(3/5)t+5t^(2)`
`300=20t+t^(2) rArr t=20s`
`:.` horizontal distance `=(u cos theta)t`
`=500/3(4/5)10=4000/3m`
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