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A man travelling at 10.8 kmph in topless...

A man travelling at `10.8 kmph` in topless car on a rainy day. He holds an umbrella at angle of `37^(@)` with the vertical so that he does not wet. If rain drops falls vertically downwards what is rain velocity.

A

`1 m//s`

B

`2 m//s`

C

`3 m//s`

D

`4 m//s`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to find the velocity of the rain given that a man is traveling in a topless car at a speed of 10.8 km/h and holds an umbrella at an angle of 37 degrees with the vertical. ### Step-by-Step Solution: 1. **Understand the Given Information:** - Speed of the man (Vm) = 10.8 km/h - Angle of the umbrella with the vertical (θ) = 37 degrees - The rain is falling vertically downwards. 2. **Convert the Speed of the Man to m/s:** \[ Vm = 10.8 \, \text{km/h} = \frac{10.8 \times 1000}{3600} \, \text{m/s} = 3 \, \text{m/s} \] 3. **Set Up the Velocity Components:** - Let Vr be the velocity of the rain (which we need to find). - The velocity of the rain with respect to the man (Vrm) makes an angle of 37 degrees with the vertical. 4. **Break Down the Velocity of Rain:** - The vertical component of the velocity of rain (Vr_vertical) can be expressed as: \[ Vr_{\text{vertical}} = Vr \cdot \cos(37^\circ) \] - The horizontal component of the velocity of rain (Vr_horizontal) can be expressed as: \[ Vr_{\text{horizontal}} = Vr \cdot \sin(37^\circ) \] 5. **Relate the Components to the Man's Velocity:** - Since the rain appears to fall vertically to the man, the horizontal component of the rain's velocity must equal the speed of the man: \[ Vr_{\text{horizontal}} = Vm \] \[ Vr \cdot \sin(37^\circ) = 3 \, \text{m/s} \] 6. **Calculate the Velocity of Rain:** - From the above equation, we can solve for Vr: \[ Vr = \frac{3}{\sin(37^\circ)} \] - Using \(\sin(37^\circ) \approx 0.6018\): \[ Vr \approx \frac{3}{0.6018} \approx 4.98 \, \text{m/s} \] 7. **Find the Vertical Component of the Rain:** - Now, we can find the vertical component: \[ Vr_{\text{vertical}} = Vr \cdot \cos(37^\circ) = 4.98 \cdot \cos(37^\circ) \] - Using \(\cos(37^\circ) \approx 0.7986\): \[ Vr_{\text{vertical}} \approx 4.98 \cdot 0.7986 \approx 3.98 \, \text{m/s} \] 8. **Final Result:** - The magnitude of the rain's velocity is approximately: \[ Vr \approx 4.98 \, \text{m/s} \] ### Conclusion: The velocity of the rain is approximately **4.98 m/s** vertically downward.

To solve the problem, we need to find the velocity of the rain given that a man is traveling in a topless car at a speed of 10.8 km/h and holds an umbrella at an angle of 37 degrees with the vertical. ### Step-by-Step Solution: 1. **Understand the Given Information:** - Speed of the man (Vm) = 10.8 km/h - Angle of the umbrella with the vertical (θ) = 37 degrees - The rain is falling vertically downwards. ...
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