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The horizontal and vertical displacement...

The horizontal and vertical displacements of a projectile are given as `x=at` & `y=bt-ct^(2)`.Then velocity of projection is

A

`sqrt(a^(2)+b^(2))`

B

`sqrt(b^(2)+c^(2))`

C

`sqrt(a^(2)+c^(2))`

D

`sqrt(b^(2)-c^(2))`

Text Solution

Verified by Experts

The correct Answer is:
A
`u_(x)=(dx)/dt,u_(y)=(dx)/dt` and `u=sqrt(u_(x)^(2)+u_(y)^(2))`
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