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If the time of flight of a projectile is...

If the time of flight of a projectile is doubled, what happens to the maximum height at tained?

A

halved

B

remains unchanged

C

doubled

D

become four times

Text Solution

Verified by Experts

The correct Answer is:
D
`H=(gT^(2))/8`
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Knowledge Check

  • The time of flight of the projectile is:

    A
    `asqrt(2/(bg))`
    B
    `a/sqrt(bg)`
    C
    `sqrt((2a)/(bg))`
    D
    `sqrt(a/(2bg))`

  • The relation between the time of flight of projectile T_f and the time to reach the maximum height T_m is

    A
    `T_f = 2T_m`
    B
    `T_f = T_m`
    C
    `T_f = (T_m)/(2)`
    D
    `T_f = sqrt(2) (T_m)`

  • The relation between the time of flight of projectile T_(f) and the time to reach the maximum height t_(m) is

    A
    `T_(f) = 2t_(m)`
    B
    `T_(f) = t_(m)`
    C
    `T_(f) = (t_(m))/(2)`
    D
    `T_(f) = sqrt(2)(t_(m))`

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    Explore conceptually related problems

    The time of flight of a projectile is 10 s and range is 500m. Maximum height attained by it is [ g=10 m//s^(2) ]

    An object is projected with speed u and range of the projectile is found to be double of the maximum height attained by it . Range of the projectile is .

    An object is projected with speed u and range of the projectile is found to be double of the maximum height attained by it . Range of the projectile is .

    Assertion : If time of flight in a projectile motion is made two times, its maximum height will become four times. Reason : In projectile motion H prop T^2 , where H is maximum height and T the time of flight.

    The speed of a projectile at its maximum height is sqrt3//2 times its initial speed. If the range of the projectile is n times the maximum height attained by it, n is equal to :

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