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Two particles are projected in air with speed `v_(0)` at angles `theta_(1)` and `theta_(2)` (both acute) to the horizontal,respectively.If the height reached by the first particle greater than that of the second,then thick the right choices

A

angle of projection:`theta_(1)gt theta_(2)`

B

time of flight:`T_(2) gt T_(1)`

C

horizontal range:`R_(1) gt R_(2)`

D

total energy : `U_(1) gt U_(2)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, C
`H_(1)gtH_(2)`
`sin theta_(1)-sin theta_(2)` or `theta_(1)gttheta_(2)`
`T_(1)gtT_(2)`
`R_(1)/R_(2)=(sin 2theta_(1))/(sin 2theta_(2))gt1`
`U_(1)=KE+PE=1/2m_(1)v_(0)^(2)`
`U_(2)=KE+PE=1/2m_(2)v_(0)^(2)`
If `m_(1)=m_(2)` then `U_(1)=U_(2)`
`m_(1)gtm_(2)` then `U_(1)gtU_(2)`
`m_(1)ltm_(2)` then `U_(1)ltU_(2)`
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